4x^2-15x-250=0

Solution for 4x^2-15x-250=0 equation:

4x^2-15x-250=0

a = 4; b = -15; c = -250;
Δ = b2-4ac
Δ = -152-4·4·(-250)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-65}{2*4}=\frac{-50}{8}
=-6+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+65}{2*4}=\frac{80}{8}
=10
$